Consecutive Odd Numbers and the Pellian Equation(Part XIXB)

Continuation:A Method for Generating Pellian Triples

The Pellian equation x2 − Dy2 = 1 was covered in Part I and the negative Pellian equation x2 − Dy2 = −1 in Part II. The least solutions of the negative Pell equation, however, are not posted in either Wikipedia (which has a small section describing this topic) or listed in Recreations in the Theory of Numbers by Albert H. Beiler (1966) as were their positive Pell solutions, but the following equations on page 253 may be used for their computation:

x = [(p + qD)2n-1 + (p − qD)2n-1 ∕ 2]
y = [(p + qD)2n-1 + (p − qD)2n-1 ∕ 2D)]

In addition, the method of converting a quadratic surd D into continued fractions (pages 261-262) are also methods that can be used to generate these least solutions. On the other hand, this method is now available on this website as a computer program making it extremely easy to generate the convergents.

This article, a continuation of Part XIXA, is in regard to the sequences Sn generated from the the equations of the type N(n)(n+1) + m which have very interesting properties as was shown in Part XVII for 4(n)(n+3) + 5 and in Part IIIA for 4(n)(n+1) + 5. Six other sequences with similar equations are displayed below and two of the sequences, 36(n)(n+1) + 13 and 36(n)(n+1) + 5 were found to be subsets of the equations ending above in 5 and −3, respectively:

Sn3 = 36(n)(n+1) + 3
3, 75, 219, 435, 723, 1083, 1515, 2019, 2595, 3243, 3963, ...

Sn5 = 36(n)(n+1) + 5
5, 77, 221, 437, 725, 1085, 1517, 2021, 2597, 3245, 3965, ...

Sn7 = 36(n)(n+1) + 7
7, 79, 223, 439, 727, 1087, 1519, 2023, 2599, 3247, 3967, ...
--------------------------------------------------------------------------
Sn11 = 36(n)(n+1) + 11
11, 83, 227, 443, 731, 1091, 1523, 2027, 2603, 3251, 3971, ...

Sn13 = 36(n)(n+1) + 13
13, 85, 229, 445, 733, 1093, 1525, 2029, 2605, 3253, 3973, ...

Sn15 = 36(n)(n+1) + 15
15, 87, 231, 447, 735, 1095, 1527, 2031, 2607, 3255, 3975, ...

where all the sequences were evaluated at n ≥ 0. No values exist for Sn9 = 36(n)(n+1) + 9 (dashed line), since the terms generated are perfect square integers which are not allowed as values of D in the Pell equation and, consequently, when used in the program to calculate convergents will result in a "no integer solution".

All the terms above (the D values) were entered into the Pell calculator program to give values of Qn = +1 for different values of n. It should be noted that the x and the y terms are found at the bottom of column n − 1 just to the left of Qn in the coded examples. We can see that in the six coded examples: for 723 at Code 723; for 725 Code 725; for 727 at Code 727; for 1091 at Code 1091; for 1093 Code 1093; and for 1095 Code 1095. The red numbers 3 and 5 although generated by the equation in sequence Sn3 do not share the properties of the numbers under discussion since their Qn = 1 at n = 3,5,7,... for D = 3 and n = 1,1,1,... for D = 5 (see Code 3 and Code 5).

Tables of x, y and D values

Tables I-VI show the first 11 D numbers in the six different sequences Sn. Although the values of D equal 3 and 5 in Tables I and II, respectively, they are tabulated even though they do not have the requisite properties, i.e., Qn = 1 shared with the other D terms of the equations.

Table I (Sn3)
D375219435723108315152019259532433963
x2267414624236250667486610821322
y13579111315171921
Table II (Sn5)
D577221437725108515172021259732453965
x93511665459998011791929601454956624992511 124929
y4401122203645447601012130016241984
yf4(1)4(10)4(28)4(55)4(91)4(136)4(190)4(253) 4(325)4(406)4(496)
Table III (Sn7)
D779223439727108715192023259932473967
x880224440728108815202024260032483968
y39152127333945515763
Table IV (Sn11)
D1183227443731109115232027260332513971
x1082226442730109015222026260232503970
y39152127333945515763
Table V (Sn13)
D1385229445733109315252029260532533973
x183781710466298821801829718456306640292682 125118
y5411132213655457611013130116251985
xf1(18)3(126)5(342)7(666)9(1098)11(1638) 13(2286)15(3042)17(3906)19(4878)21(5958)
Table VI(Sn15)
D1587231447735109515272031260732553975
x4287614824436450867686810841324
y13579111315171921

where the values of y for Sn3, Sn7, Sn11 and Sn15 and the values of x in Sn13 are the consecutive odd numbers. For Sn5, on the other hand, y is now a non consecutive triangular number ½[(3m + 1)2 + (3m + 1)]. Lastly, from the tables we can see that x takes on the following values as symmetrical ± pairs:

x = ⅓D + 1 in Table I
x = ½(D + 3) in Table II
x = D + 1 in Table III
x = D − 1 in Table IV
x = ½(D − 3) in Table V
x = ⅓D − 1 in Table VI

Tables of Pell Equations

The Pell equations are set up according to the following formats with the x and ys taken from the above six tables. The first expression with n1 gives the alternate expression for x + yD where the square term is divided by either 2 or 6 and n1 is a consecutive odd number = 3(2n + 1). The second expression with n2 gives the alternate expression x + yD for Sn5 and Sn13 where n2 is a consecutive odd number × 3. Again in four out of six cases y is a consecutive odd number, in another it is a triangular number, and in the last case it is x which is the odd consecutive number.

RD = (n1 + D)2 ∕ 2 or 6 = x + yD
RD = [(n2 + D)2 ∕4]3∕2 = x + yD

Tables VII-IX give the formulas for all 10 Pell equations according to the format listed above with the triangular and odd numbers in blue.

Table VII
(Sn3) Equal Expressions(Sn15) Equal Expressions
R75 = (3(3) + 75)2 ∕6 = 26 + 375 R15 = (3(1) + 15)2 ∕6 = 4 + 115
R219 = (3(5) + 219)2 ∕6 = 74 + 5219 R87 = (3(3) + 87)2 ∕6 = 28 + 387
R435 = (3(7) + 435)2 ∕6 = 146 + 7435 R231 = (3(5) + 231)2 ∕6 = 76 + 5231
R723 = (3(9) + 723)2 ∕6 = 241 + 9723 R447 = (3(7) + 447)2 ∕6 = 148 + 7447
R1083 = (3(11) + 1083)2 ∕6 = 362 + 111083 R735 = (3(9) + 735)2 ∕6 = 244 + 9735
R1515 = (3(13) + 1515)2 ∕6 = 506 + 131515 R1095 = (3(11) + 1095)2 ∕6 = 364 + 111095
R2019 = (3(15) + 2019)2 ∕6 = 674 + 152019 R1527 = (3(13) + 1527)2 ∕6 = 508 + 131527
R2595 = (3(17) + 2595)2 ∕6 = 866 + 172595 R2031 = (3(15) + 2031)2 ∕6 = 676 + 15203
R3243 = (3(19) + 3243)2 ∕6 = 1082 + 193243 R2607 = (3(17) + 2607)2 ∕6 = 868 + 172607
R3963 = (3(21) + 3963)2 ∕6 = 1322 + 213963 R3255 = (3(19) + 3255)2 ∕6 = 1084 + 193255
Table VIII
(Sn5) Equal Expressions(Sn13) Equal Expressions
R5 = [(3(1) + 5)2 ∕4]3/2 = 9 + 4(1)5 R13 = [(3(1) + 13)2 ∕4]3/2 = 1(18) + 513
R77 = [(3(3) + 77)2 ∕4]3/2 = 351 + 4(10)77 R85 = [(3(3) + 85)2 ∕4]3/2 = 3(126) + 4185
R221 = [(3(5) + 221)2 ∕4]3/2 = 1665 + 4(28)221 R229 = [(3(5) + 229)2 ∕4]3/2 = 5(342) + 113229
R437 = [(3(7) + 437)2 ∕4]3/2 = 4599 + 4(55)437 R445 = [(3(7) + 445)2 ∕4]3/2 = 7(666) + 221445
R725 = [(3(9) + 725)2 ∕4]3/2 = 9801 + 4(91)725 R733 = [(3(9) + 733)2 ∕4]3/2 = 9(1098) + 365733
R1085 = [(3(11) + 1085)2 ∕4]3/2 = 17919 + 4(136)1085 R1093 = [(3(11) + 1093)2 ∕4]3/2 = 11(1638) + 5451093
R1517 = [(3(13) + 1517)2 ∕4]3/2 = 29601 + 4(190)1517 R1525 = [(3(13) + 1525)2 ∕4]3/2 = 13(2286) + 7611525
R2021 = [(3(15) + 2021)2 ∕4]3/2 = 45495 + 4(253)2021 R2029 = [(3(15) + 2029)2 ∕4]3/2 = 15(3042) + 10132029
R2597 = [(3(17) + 2597)2 ∕4]3/2 = 66249 + 4(325)2597 R2605 = [(3(17) + 2605)2 ∕4]3/2 = 17(9486) + 13012605
R3245 = [(3(19) + 3245)2 ∕4]3/2 = 92511 + 4(406)3245 R3253 = [(3(19) + 3253)2 ∕4]3/2 = 19(4878) + 16253253
Table IX
(Sn7) Equal Expressions(Sn11) Equal Expressions
R7 = (3(1) + 7)2 ∕2 = 8 + 3(1)7 R11 = (3(1) + 11)2 ∕2 = 10 + 3(1)11
R79 = (3(3) + 79)2 ∕2 = 80 + 3(3)79 R83 = (3(3) + 83)2 ∕2 = 82 + 3(3)83
R223 = (3(5) + 223)2 ∕2 = 224 + 3(5)223 R227 = (3(5) + 227)2 ∕2 = 226 + 3(5)227
R439 = (3(7) + 439)2 ∕2 = 440 + 3(7)439 R443 = (3(7) + 443)2 ∕2 = 442 + 3(7)443
R727 = (3(9) + 727)2 ∕2 = 728 + 3(9)727 R731 = (3(9) + 731)2 ∕2 = 730 + 3(9)731
R1087 = (3(11) + 1087)2 ∕2 = 1088 + 3(11)1087 R1091 = (3(11) + 1091)2 ∕2 = 1090 + 3(11)1091
R1519 = (3(13) + 1519)2 ∕2 = 1520 + 3(13)1519 R1523 = (3(13) + 1523)2 ∕2 = 1522 + 3(13)1523
R2023 = (3(15) + 2023)2 ∕2 = 2024 + 3(15)2023 R2027 = (3(15) + 2027)2 ∕2 = 2026 + 3(15)2027
R2599 = (3(17) + 2599)2 ∕2 = 2600 + 3(17)2599 R2603 = (3(17) + 2603)2 ∕2 = 2602 + 3(17)2603
R3247 = (3(19) + 3247)2 ∕2 = 1322 + 3(19)3247 R3255 = (3(19) + 3255)2 ∕2 = 1084 + 3(19)3255

This concludes Part XIXB. To go to the next continuation Part XIXC.
To go back to Part XIXA.

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