The Diophantine Equation x2 ± D(∑ yj2) = z2 (Multiples) (Part XI)

A Method of Generating Multiples from Novel Equations

Previous sections, e.g., Part III and Part III produced Diophantine triples and quadruples using the Diophantine equation x2 + D(∑ yj2) = z2. The previous section Part X discussed the higher diophantine multiples, viz., the quintuples, sextuples using the same equation with more yj values.

This new method produces multiples from a set of novel equations generating the variables x, y1, y2, ..., ym and z, where there occur multiple variables of y. The first example using the variables x, y1, y2, y3 and z for the quintuples as well as the equations listed in table A1 according to the following format:

Table A1
δ1x y1y2y3 z δ2
a1a2a3 D(a12 + a22 + a32) - n2 2na12na22na3 D(a12 + a22 + a32) + n2

The equations are similar in form to the equations for obtaining the 3 legs of the Pythagorean integers X = m2n2, Y = 2mn, and Z = m2n2 except that the generating numbers are not limited to only two numbers. In addition, a1, a2 and a3 are generating numbers, D is any integer greater than zero and the (n2, 2n) are values taken from table B:

Table B (n2 & 2n values)
n2149162536496481100...
2n2468101214161820...

Since there are an infinite number of (n2, 2n) integers there are also an infinite number of tables which can be tabulated with their accompanying equations. In addition, the multiples which are generated may be present in primitive or non primitive form, where non primitives may be converted to primitive forms by dividing out any common factors.

Previous tables have been constructed using values of 1 to 9 as generating numbers. A new table is shown with numbers in these left hand columns greater than zero showing that these columns can accommodate generating numbers greater than zero.

Table I depicts 2 quintuples with their respective aj, D and n values and where D and n interchange their values.

Table I (D = 3, n= 4; D = 4, n = 3)
δ1x y1y2y3 z δ2
a1a2a3 D(a12 + a22 + a32) - n2 2na12na22na3 D(a12 + a22 + a32) + n2
1719233(289 + 361 + 529) − 16 = 35211361521843(289 + 361 + 529) + 16 = 3553
1719234(289 + 361 + 529) − 9 = 47071021241584(289 + 361 + 529) + 9 = 4725

Plugging these values into the equation:

x2 + D(y12 + y22 + y32) = z2
35212 + 3(1362 + 1522 + 1842) = 12397441 + 3(18496 +23104 + 33856) = 12623809 = 35532
47072 + 4(1022 + 1142 + 1382) = 22155849 + 4(10404 +12996+ 19044) = 263225625 = 47252

confirming the z values of Table I.

The Equivalence of the Left and Right Hand Sides of Equation x2 + D(∑ yj2) = z2

We can show that the left and right hand sides of the general equation x2 + D(∑ yj2) = z2 are equal by looking first at an equation that contains only one aj:

(Da12 − n2)2 + D(2na1)2 = (Da12 + n2)2
D2a14 − 2Dn2a12 + n4 + 4Dn2a12 = (Da12 + n2)2
D2a14 + 2Dn2a12 + n4 = (Da12 + n2)2

which shows that the left hand side equals the right hand side. If we add more aj for example an a2 we get:

(D(a12 + a22) − n2)2 + D[(2na1)2 + (2na2)2] = [D(a12 + a22) + n2]2
D2(a12 + a22)2 − 2D(n2a12 + n2a22) + n4 + 4D(n2a12 + n2a22) =
[D(a12 + a22) + n2]2
D2(a12 + a22)2 + 2D(n2a12 + n2a22) + n4 =
[D(a12 + a22) + n2]2

Therefore, the addition of more aj will result in an equation containing more and more aj with the proviso that the left hand side of the equation will always equal the right hand side.

This concludes Part XI. Go back to Part X.

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