NEW SEQUENCE OF SQUARES
GENERATION OF PARTIAL MAGIC SQUARE OF SQUARES
Square of Square Sequences
Andrew Bremner's article on squares of squares included the 3x3 square:
Bremmer's square
582 | 462 | 1272 |
942 | 1132 | 22 |
972 | 822 | 742 |
The numbers in the right diagonal as the tuple (972,1132,1272) appears to have come out of the blue. But I will show that
this sequence is part of a larger sequence of numbers which can be broken down into tuples having the same property, i.e. the first number in the tuple when added to a
difference (Δ) gives the second square in the tuple and when this same (Δ)
is added to the second square produces a third square. All these tuple sequences can be used as entries into the right diagonal of a magic square.
These sequnces will be shown to have special properties where the diffence between numbers generates other sequences.
Construction of two Sequences
- The first sequence constructed generates a non-square Sequence I.
- We begin using equation ½(n2 - 2n - 1) where
n is initially 3. This gives the number 1 in Sequence I.
- Applying equation ½(n2 + 1) next gives us the number 5.
- Then applying equation ½(n2 + 2n - 1) next gives us the number 7.
- This completes one cycle. Incrementing n by two gives us 5 and the next number to substitute into the first equation
to repeat the cycle.
- Since the number generated using n1 for n in
½(n2 + 2n - 1)
is identical to ( n1 +2 ) for n in
½(n2 - 2n - 1) the second identical number is not used in the sequence.
Equations
| | ½(n2 + 1) | | |
| ↗ | | ↘ | |
½(n2 - 2n - 1) | | ← | |
½(n2 + 2n - 1) |
This can be generalized tothe following sequence having the Sloane Number A178218:
which may be found in the catalogue of numbers:
1, [½(n2 + 1), ½(n2 + 2n - 1)]N
such that as N ⇒ N + 1, n ⇒ n + 2, i.e., as N goes through each cycle n increases by 2.
- The sequence can be generated by an alternative general method The Generation of New Sequences (Part G) discovered in 9/2012
and stored on this website.
- The sequence generated goes up to the number 577 and is shown below in white. (To generate a larger sequence see below).
- The second sequence in green and tan shows the differences between numbers as an interleaved (alternating array) of numbers. One is
(4,6,8,10,...),
the other at (2,4,6,8,10,...). Thus by knowing the first two numbers in the sequence, (viz. 1 and 5) the sequence can be
generated. The three consecutive numbers (97, 113, 127), as their squares, are one of the diagonals of the Bremmer's square.
- The Bremner square. however, is not magic since the sum of the right diagonal is 38307 while all other sums are 21609.
- If we square all the numbers in the first sequence we obtain the Sequence table II. The entries (in color) between squares is the difference
(Δ) between numbers in the right diagonal tuple (a2, b2, c2) of a magic square.
Sequence of Numbers I
1 | | 5 | | 7 | | 13 |
| 17 | | 25 | | 31 | |
41 | |
49 | | 61 | | 71 |
|
| 4 | | 2 | | 6 |
| 4 | | 8 | | 6 |
| 10 | | 8 | | 12 |
| 10 | | 14 |
|
85 | | 97 | | 113 | |
127 | | 145 |
| 161 | | 181 | | 199 | |
221 | | 241 | | 265 | |
| 12 | | 16 |
| 14 | | 18 | | 16 |
| 20 | | 18 | | 22 |
| 20 | | 24 |
| 22 |
|
287 | | 313 | | 337 | |
365 | | 391 | | 421 |
| 449 | | 481 | |
511 | | 545 | | 577 |
|
| 26 | | 24 | | 28 |
| 26 | | 30 | | 28 |
| 32 | | 30 | | 34 |
| 32 | | 36 |
Sequence of Squares II
1 | | 25 | | 49 | | 169 |
| 289 | | 625 | | 9611 | |
| 24 | | 24 | | 120 |
| 120 | | 336 | | 336 |
| 720 |
|
1681 | | 2401 | | 3721 | | 5041 |
| 7225 | | 9409 | | 12769 | |
| 720 | | 1320 | | 1320 |
| 2184 |
| 2184 | | 3360 | | 3360 |
|
16129 | | 21025 | | 25921 | | 32761 |
| 39601 | |
48841 | | 58081 | |
| 4896 | | 4896 | |
6840 | | 6840 | | 9240 |
| 9240 |
| 12144 |
|
70225 | | 82369 | | 97969 | |
113569 | | 133225 | | 152881 | |
177241 | |
| 12144 | | 15600 |
| 15600 | | 19656 | |
19656 | | 24360 | | 24360 |
|
| 201601 | |
231361 | | 261121 | | 297025 | | 332929 |
| 29760 | | 29760 |
| 35904 | | 35904 | |
- If we modify Bremner's square, magic square A can be generated. Another example of a magic square (B) produced from the tuple
(337, 365, 391), as their squares, also obtained from the sequence table I is shown below. The magic sum in this case is 399675.
Magic square A
582 | 18814 | 1272 |
25534 | 1132 | 22 |
972 | 822 | 22174 |
|
| |
Magic square B
2552 | 181769 | 3912 |
221081 | 3652 | 2132 |
3372 | 2912 | 207425 |
|
- If we take the difference of squares from above and divide each by 24 and throw out duplicates, the following sequence is found (first array).
The second sequence is the difference of differences and shows that the natural number sequence of squares is generated (in yellow). So what started out as
a method for generating consecutive squares led us back to the natural numbers.
Difference of Squares
1 | | 5 | | 14 | | 30 |
| 55 | | 91 | | 140 | |
204 | |
| 4 | | 9 | | 16 |
| 25 | | 36 | | 49 |
| 64 | | 81 |
|
285 | | 385 | | 506 |
| 650 | | 819 | | 1015 | |
1240 | | 1496 |
| 100 | | 121 | | 144 |
| 169 | | 196 | |
225 | | 256 | |
The Sequence Extended
Below is shown a copy of a program used to generate the sequence with 75 and 100 entries.
function sequence(r)
/* r is used as an argument when the function is called */
{
var a=0; var c=0;
print a 1 to start the sequence
for (n=3; n<=r;n++) /*Cycle thru N, n starts at 3*/
{
a= (n*n + 1)/2;
c= (n*n +2*n - 1)/2;
print a and c
n=n+1;
}
}
To go back up.
This concludes the new sequence of squares. The next page treats the same topic but the entries for the right diagonals
are tabulated and each row calculated using algebraic equations.
Go back to homepage.
Copyright © 2010 by Eddie N Gutierrez. E-Mail: Fiboguti89@Yahoo.com